Hello,

I'm going through chapter 19 of the ASM manual. There's a practice problem that gives the following table

[x] l_[x] l_[x]+1 l_[x]+2

30 10000 9000 8000

31 9500 8500 7500

32 9200 8100 7000

As part of the solution for the problem involving pure endowments, 3_p_[30] is calculated as l_[30]+3 / l_[30] = 7500/10000.

If this is true, shouldn't this be a 2 year select and ultimate mortality table, i.e. the heading on the last column should be l_x+2 ?

I'm going through chapter 19 of the ASM manual. There's a practice problem that gives the following table

[x] l_[x] l_[x]+1 l_[x]+2

30 10000 9000 8000

31 9500 8500 7500

32 9200 8100 7000

As part of the solution for the problem involving pure endowments, 3_p_[30] is calculated as l_[30]+3 / l_[30] = 7500/10000.

If this is true, shouldn't this be a 2 year select and ultimate mortality table, i.e. the heading on the last column should be l_x+2 ?

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