Banner Ad 1

Collapse

Announcement

Collapse
No announcement yet.

Question from Actex study guide

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • Question from Actex study guide

    Let X_1 and X_2 form a random sample from a Poisson distribution. The Poisson distribution has a mean of 1. If Y=min{X_1,X_2}, then P[Y=1]?

    I know P[Y=1]=P[X_1=1vX_2=>1] + P[X_2=1vX_1=>2]. Why is X_1=>2 and not 1?

  • #2
    Hi Robert,

    Because we already accounted for the combination X1=1 and X2=1 in the first part of the calculation!

    Rathi

    Comment

    Working...
    X