how to integrate f(x,y)=ye^xy , 0<x<1,0<y<1
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a question  how to integrate f(x,y)=ye^xy , 0<x<1,0<y<1
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a question  how to integrate f(x,y)=ye^xy , 0<x<1,0<y<1
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answer to your question................. f(x,y)=ye^xy ; 0<x<1, 0<y<1  Integral = I Upperlimit = UL Lower Limit = LL  f(x,y)=(I,LL:0,UL:1,for x)((I,LL:0,UL:1,for y)ye^xy dydx Use integration by parts, enter the upper and lower limitand you would endup with(I,LL:0,UL:1,for x)[(1/x)e^(x)]dxnow integrate [(1/x)e^(x)] with respect to x and enter the value of limits (LL=0,UL=1) and you would have (e^1)e^0 which is same as (e^1)1which is equal to 1.71828......that should be your answer.

sorry the answer is e^12 i do have the solution book with me..
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I did that question again and I see my mistake but still I didn't get the answer you have...........can you look at it and let me know what mistake I made.... ye^xy w.r.t dydx both integrals limit (0 to 1)integrate w.r.t dy we have [{(y^2)(e^(xy))} / 2] after inserting the limits we have(e^x)/2 dxnow integrate w.r.t dx we get .5e^x insert limits (0,1).5e  .5which is equal to .85 that should be the answerif not can you check my work.
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yah the solution given below that is 27 feb 2005 is correct
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keep y fixed and integrated with x variable.you should have e^y  1.now integrate (e^y 1)dy 0<y<1.if I'm not mistaking the answer should be e 2
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