From example 7-8 of the Actex 2007 manual, you have to find the integral from 0 to 50 of k*(x^5)((100-2x)^6)dx. The manual uses the beta distribution (to find the mean of a pdf of X that is proportional to x^4(100-2x)^6 on the interval 0<x<50). Isn't there a way to do this without using the beta distribution and without having to multiply out (100 - 2x)^6?

Thanks!!

Thanks!!

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