P/1 Actex - Problem Set 6, problem # 9

[bubbarobert8]

I apologize in advance for what many of you will find to be a simpleton question.

Would someone mind walking me through the algebraic manipulation in this problem? I completely understand how to get to:

e^-lamda * lamda^2 / 2 = 3e^-lamda * lamda^4 / 24

Unfortunately, I'm not following how that gets simplified to lamda = 2.

Thanks for any help, I really appreciate it!

[NoMoreExams]

I apologize in advance for what many of you will find to be a simpleton question.

Would someone mind walking me through the algebraic manipulation in this problem? I completely understand how to get to:

e^-lamda * lamda^2 / 2 = 3e^-lamda * lamda^4 / 24

Unfortunately, I'm not following how that gets simplified to lamda = 2.

Thanks for any help, I really appreciate it!

Sure, get everything with e^''''..} on one side so you get

e^{-lambda} / (3e^{-lambda} = (lambda^4 / 24) / (lambda^2 / 2) =>

1/3 = lambda^2 / 12 =>

4 = lambda^2 =>

lambda = +/-2

P.S. it's lambda not "lamda"

[bubbarobert8]

Thanks so much! This is very helpful!!

[bubbarobert8]

Time for a study break!

Ok, I totally feel like a moron now. Time for an hour break from studying.