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P/1 Actex - Problem Set 6, problem # 9

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  • P/1 Actex - Problem Set 6, problem # 9

    I apologize in advance for what many of you will find to be a simpleton question.

    Would someone mind walking me through the algebraic manipulation in this problem? I completely understand how to get to:

    e^-lamda * lamda^2 / 2 = 3e^-lamda * lamda^4 / 24

    Unfortunately, I'm not following how that gets simplified to lamda = 2.

    Thanks for any help, I really appreciate it!

  • #2
    Originally posted by bubbarobert8 View Post
    I apologize in advance for what many of you will find to be a simpleton question.

    Would someone mind walking me through the algebraic manipulation in this problem? I completely understand how to get to:

    e^-lamda * lamda^2 / 2 = 3e^-lamda * lamda^4 / 24

    Unfortunately, I'm not following how that gets simplified to lamda = 2.

    Thanks for any help, I really appreciate it!
    Sure, get everything with e^''''..} on one side so you get

    e^{-lambda} / (3e^{-lambda} = (lambda^4 / 24) / (lambda^2 / 2) =>

    1/3 = lambda^2 / 12 =>

    4 = lambda^2 =>

    lambda = +/-2

    P.S. it's lambda not "lamda"

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    • #3
      Thanks so much! This is very helpful!!

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      • #4
        Time for a study break!

        Ok, I totally feel like a moron now. Time for an hour break from studying.

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