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question on general probability problem

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  • question on general probability problem

    Problem:
    A,B and C are three possible events. Pr(at least one event occurs) = 0.9. Pr(exactly two events occur) = 0.02. Pr(exactly one event occurs) = 0.36. If C and A, as well as C and B are mutually independent, what is Pr(C)?
    Question:
    I found Pr(A and B and C)=0.52.
    Then C-AC-BC=0.9-A-B+(A and B)-.52
    C(1-A-B)=0.38-(A or B)
    I'm getting stuck here on this step. I would appreciate your help.

  • #2
    Please disregard my post. I couldn't delete it.
    Last edited by bsd058; January 28 2012, 04:31 AM.

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    • #3
      does anyone have an idea how to solve this one? thank you

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      • #4
        would like to know this as well.. tried to do it but i'm stuck..

        is Pr(exact 1 event occurs) = Pr(AnB'nC')*Pr(A'nBnC')*Pr(A'nB'nC) , or is each of those =.36?

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        • #5
          Originally posted by latebloomer View Post
          would like to know this as well.. tried to do it but i'm stuck..

          is Pr(exact 1 event occurs) = Pr(AnB'nC')*Pr(A'nBnC')*Pr(A'nB'nC) , or is each of those =.36?
          It should be Pr(exactly 1 event occurs) = (AnB'nC') U (A'nBnC') U (A'nB'nC) = .36 Still haven't figured out the solution though..

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