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  • A probability question?

    Q::Two people agree to meet at a train station between 5:00 p.m and 5:30 p.m , and they agreed that neither person will wait for the other for more than 10 minutes..If each person arrives independently at random betwen 5:00 p.m and 5:30 p.m . what is the probability that they will meet?
    please give solution.

  • #2
    Originally posted by insaan
    Q::Two people agree to meet at a train station between 5:00 p.m and 5:30 p.m , and they agreed that neither person will wait for the other for more than 10 minutes..If each person arrives independently at random betwen 5:00 p.m and 5:30 p.m . what is the probability that they will meet?
    please give solution.
    I would draw a square with each side 30 (1 unit = 1 minute). Then, shade in the part of the square that represents X being greater than Y by 10, or Y being greater than X by 10. Both of these shapes should be triangles. Find the area of both triangles, add them together, subtract from 900 = area of square, then divide by 900. For the actual numbers:

    Area of triangle where X < Y by 10: (20)*(20)*(1/2) = 200.
    Area of triangle where Y < X by 10: (20)*(20)*(1/2) = 200.

    Thus, total area of the triangles = 400.

    --> P(within 10 minutes of each other) = 1 - (P(not within 10 minutes of each other)
    = 1 - [(200/900)+(200/900)] = 500/900 = 5/9.

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    • #3
      thanks

      thanks for your reply
      it was a nice explanaion and i got the answer very easilyand quckly

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