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  • August 2007 Question

    There were two particular questions that I remember I had trouble with.

    The first was something about a large pool of people that were divided into Males, Females, Smokers, and Nonsmokers. We were given that there were 350 total Smokers, 150 more female Nonsmokers compared to male nonsmokers, and then also given another bit of information which I do not remember. Does anyone recall this question and how they solved it?

    Another question that I had difficulty with, and this question actually showed up during my November test as well, was one about rainfall. An insurance policy covers damage for every 10 inches of rain in excess of 40 inches. We were given a probability table of the amount of rain and the probability of this occuring. I believe the question was to determine the expected payment. Did anyone get this question and solve it correctly?

    Thanks.

  • #2
    Originally posted by crystal0
    There were two particular questions that I remember I had trouble with.

    The first was something about a large pool of people that were divided into Males, Females, Smokers, and Nonsmokers. We were given that there were 350 total Smokers, 150 more female Nonsmokers compared to male nonsmokers, and then also given another bit of information which I do not remember. Does anyone recall this question and how they solved it?

    Another question that I had difficulty with, and this question actually showed up during my November test as well, was one about rainfall. An insurance policy covers damage for every 10 inches of rain in excess of 40 inches. We were given a probability table of the amount of rain and the probability of this occuring. I believe the question was to determine the expected payment. Did anyone get this question and solve it correctly?

    Thanks.
    I had trouble with the first one too. The second question I had, it was to find the std of the expected payment. We were given that for every full 10 inches above 40 the farmer would recieve $300 with a cap at 700. Now that means at 50 inches he gets 300, 60 inches 600, 70 inches 700, 80 inches 700 and I believe the probabilty of 90 or greater was zero so we didnt have to calculate this. with that I took the amounts and probabilities and found the Var(X) to calculate the answer
    Last edited by djerry81; August 27 2007, 06:09 PM. Reason: I swear whenever I save it creates typos

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    • #3
      Yea I remember BOTH question. I don't remember the first one clearly anymore, but I sure remember that it also left me confused~ Jerry was right about the rainfall problem... somehow, my answer can never be one of the answer choices... and I've calculated and calculated.. and doing it over and over again... and ended up choosing one that's the closest to it... about 258 or 263 or something... =\

      Comment


      • #4
        Originally posted by RobLin
        Yea I remember BOTH question. I don't remember the first one clearly anymore, but I sure remember that it also left me confused~ Jerry was right about the rainfall problem... somehow, my answer can never be one of the answer choices... and I've calculated and calculated.. and doing it over and over again... and ended up choosing one that's the closest to it... about 258 or 263 or something... =\
        The rainfall problem was one of the two problems that drove me nuts for the 2 times I failed exam P. The first time I had that problem, I started using the probabilities beginning with 40-50 inches, which is obviously wrong. I don't know why I didn't think of that sooner.

        Comment


        • #5
          Originally posted by crystal0
          There were two particular questions that I remember I had trouble with.

          The first was something about a large pool of people that were divided into Males, Females, Smokers, and Nonsmokers. We were given that there were 350 total Smokers, 150 more female Nonsmokers compared to male nonsmokers, and then also given another bit of information which I do not remember. Does anyone recall this question and how they solved it?

          I got this also. The answer was 50.
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          • #6
            Originally Posted by djerry81

            I had trouble with the first one too. The second question I had, it was to find the std of the expected payment. We were given that for every full 10 inches above 40 the farmer would recieve $300 with a cap at 700. Now that means at 50 inches he gets 300, 60 inches 600, 70 inches 700, 80 inches 700 and I believe the probabilty of 90 or greater was zero so we didnt have to calculate this. with that I took the amounts and probabilities and found the Var(X) to calculate the answer
            dJerry81, would you please explain how you were able to just take the amounts and probabilities to find Var(X)?

            So, we were given something like (I am making up the probabilities):
            Inches of Rainfall Probability
            10 < x <= 20______.06
            20 < x <= 30______.05
            30 < x <= 40______.04
            40 < x <= 50______.03
            50 < x <= 60______.02
            60 < x <= 70______.01

            Since the payment, Y, is discrete, and the rainfall, X, seems to be continuous...Do you still multiply the appropriate probability with the dollar amount?

            For example, to calculate the expected payment, E(Y) = .03 * 300 + .02 * 600 + .01 * 700 + ...

            Thank you.

            Comment


            • #7
              Originally posted by crystal0
              dJerry81, would you please explain how you were able to just take the amounts and probabilities to find Var(X)?

              So, we were given something like (I am making up the probabilities):
              Inches of Rainfall Probability
              10 < x <= 20______.06
              20 < x <= 30______.05
              30 < x <= 40______.04
              40 < x <= 50______.03
              50 < x <= 60______.02
              60 < x <= 70______.01

              Since the payment, Y, is discrete, and the rainfall, X, seems to be continuous...Do you still multiply the appropriate probability with the dollar amount?

              For example, to calculate the expected payment, E(Y) = .03 * 300 + .02 * 600 + .01 * 700 + ...

              Thank you.
              Sorry for not being so clear LOL but I skipped a bunch of steps........First find expected payment or E[X] then E[X^2]....starting with 50in
              just as you have done above then plug into the variance formula and then viola.

              I want to also point out to do you that you that on the May exam there were questions were given only enough information to calculate Cov from the definition. I know this problem was not like that but I just wanted to make you all aware that you could find according to definition only.
              Last edited by djerry81; August 31 2007, 10:02 AM. Reason: skipped something important

              Comment


              • #8
                I thought that since you receive a payment once the rainfall hits 50 inches, the the expectation would start with .02 x 300 + ..... I believe though on the exam that the ranges were like this, with the "or equal to" part in front of the x.

                Inches of Rainfall Probability
                10 <= x < 20______.06
                20 <= x < 30______.05
                30 <= x < 40______.04
                40 <= x < 50______.03
                50 <= x < 60______.02
                60 <= x < 70______.01

                Comment


                • #9
                  Originally posted by crystal0
                  There were two particular questions that I remember I had trouble with.

                  The first was something about a large pool of people that were divided into Males, Females, Smokers, and Nonsmokers. We were given that there were 350 total Smokers, 150 more female Nonsmokers compared to male nonsmokers, and then also given another bit of information which I do not remember. Does anyone recall this question and how they solved it?

                  Thanks.
                  i had this question aswell.

                  i think the question said. there are 350 smokers, 150 more males then females and 100 more female nonsmokers then male nonsmokers.

                  First made the circles overlapping each other. (brain freeze cant remember the name of this)

                  each circle represented male, female and smoker

                  pr(smoker and not female or male ) = 0
                  pr( male and female and nonsmoker) = 0
                  pr(male and female and smoker) = 0

                  then i set male and nonsmoker as X
                  female and nonsmoker would then be 100 + x
                  male i set to 150 + y
                  female i set to y

                  once i had that set up i realized being a male and nonsmoker which i had as X was irrelivent so i put a 0 for that so female nonsmoker was just 100. then i could easily see to put 50 into female smokers and 300 into male smokers.

                  smokers = 350, 50 females and 300 males
                  males = 150 + "females" females was just 100 nonsmokers + 50 smokers
                  so males = 150 + 150 = 300
                  300 males = 0 nonsmokers and 300 smokers

                  answer is 50.

                  sorry if its hard to follow, but thats how i did it.

                  just make the diagram and you will see what i meant.

                  Comment


                  • #10
                    Originally posted by Chitown26
                    I thought that since you receive a payment once the rainfall hits 50 inches, the the expectation would start with .02 x 300 + ..... I believe though on the exam that the ranges were like this, with the "or equal to" part in front of the x.

                    Inches of Rainfall Probability
                    10 <= x < 20______.06
                    20 <= x < 30______.05
                    30 <= x < 40______.04
                    40 <= x < 50______.03
                    50 <= x < 60______.02
                    60 <= x < 70______.01
                    Now that I think about it, I really do agree with Chitown.. you have to start from 50-60 inches since they specifically indicated that for every full 10 inches in exceed of 40... which means that the payment doens't start from 50 and above... Things like this, you just wont' be able to catch it if you don't think CLEARLY enough..:skeptical:

                    Comment


                    • #11
                      Originally posted by rjkst14
                      i had this question aswell.

                      i think the question said. there are 350 smokers, 150 more males then females and 100 more female nonsmokers then male nonsmokers.

                      First made the circles overlapping each other. (brain freeze cant remember the name of this)

                      each circle represented male, female and smoker

                      pr(smoker and not female or male ) = 0
                      pr( male and female and nonsmoker) = 0
                      pr(male and female and smoker) = 0

                      then i set male and nonsmoker as X
                      female and nonsmoker would then be 100 + x
                      male i set to 150 + y
                      female i set to y

                      once i had that set up i realized being a male and nonsmoker which i had as X was irrelivent so i put a 0 for that so female nonsmoker was just 100. then i could easily see to put 50 into female smokers and 300 into male smokers.

                      smokers = 350, 50 females and 300 males
                      males = 150 + "females" females was just 100 nonsmokers + 50 smokers
                      so males = 150 + 150 = 300
                      300 males = 0 nonsmokers and 300 smokers

                      answer is 50.

                      sorry if its hard to follow, but thats how i did it.

                      just make the diagram and you will see what i meant.
                      I almost used the venn diagram, like you did with this problem......I used tables which couldnt make since of, causing me to guess on the answer

                      Comment


                      • #12
                        question

                        So what does the question about the smoker and females and males ask? what does 50 equal to? number of females?? thank you

                        Comment


                        • #13
                          cant remember what it asked. but from looking at what i wrote i would guess the question was how many female smokers are there

                          Comment


                          • #14
                            confused

                            to rjkst14,

                            sorry for not understanding but why is female and male and smoker 0? and all the other 2 parts of the venn diagram 0?? thank you in advance!

                            Comment


                            • #15
                              Originally posted by iamsammy84
                              to rjkst14,

                              sorry for not understanding but why is female and male and smoker 0? and all the other 2 parts of the venn diagram 0?? thank you in advance!
                              well just read what you said.

                              the probability of being male and female and a smoker.

                              you can be either male or female, but not both. so the probability of being male and female and anything is going to be 0.

                              and the other one is the probability of being a smoker and not female and not male. and you have to either be a male or a female to be a smoker. so that probability is 0 as well.

                              hope this helps
                              Last edited by rjkst14; September 22 2007, 03:36 PM.

                              Comment

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